Java MCQ's on Method Overloading

This test contains 10 questions based on Method Overloading.
Each question answered correctly awards you 1 point and each incorrect answer has a penalty of -0.25 points, no points are deducted for unattempted answers.

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Compile time polymorphism is also known as

Method Overriding	Method Overloading
Method Rewriting	None of these

B

Comiple Time polymorphism means that methods with same names gets resolved at the compile time only. JVM does not have to resolve these methods at runtime.

Which conditions should a method satisfy for overloading a method in a class. A.its return type should be same. B.number of parameters it takes should be different. C.type of parameters should be different.

Only A	Both A and B
Either B and C	All of the above are true.

C

For method overloading either the methods should have different number of paramaters or the type of parameters should be different.

Can we overload the constructor of a class ?

Yes

No

A

Yes, we can overload the constructors of a class as long as they satisfy the conditions of overloading.

What will happen if we try to overload the main method in a class.

Compile Time Error	Runtime Error
main method gets overloaded	None Of these

A

We can overload any method if it satisfy the overloading conditions, main method can also be overloaded. POint to remember is that the program will always start from the main method that takes "an array of Strings". All the other methods will be overloaded methods.

What will be the output of the following program ?

class Test{

 public void test(){
  System.out.print(" test1");
  }

 private void test(String s1){
  System.out.print(s1);
  this.test() ;
 }

 public static void main(String args[]){
  System.out.print(" main");
  Test obj = new Test();
  obj.test(" test2");
 }
}
 

Compile Time Error	main test1 test2
main test2 test1	None Of these

C

First "main" will be prinrted then, we call will go to the parameterized test() and "test2" will be printed and then control goes to no args test() and will print "test1"

What will be the output of the following program ?

class Test{

 public int area(int a, int b){
  System.out.println("int");
  return a * b;
  }

 public float area(float a, float b){
  System.out.println("float");
  return a * b;
 }

 public double area(double a, double b){
  System.out.println("double");
  return a * b;
 }

 public static void main(String args[]){
  Test obj = new Test();
  obj.area(1, 2.2);
  obj.area(1F, 2.2);
  obj.area(1F, 2);
 }
}
 

double float float	int double float
int float double	double double float

D

1 is an in value, 2.2 is a double value, 1F is a float value and 2 is int. So area(1,2.2) will go to area(double,double), area(1F,2.2) will also go to area(double,double) and area(1F,2) will go to area(float,float)

What will be the output of the following program ?

class Test{

 public void test(int a){
  System.out.println("int");
  }

 public float test(float a){
  System.out.println("float");
 }

 public static void main(String args[]){
  Test obj = new Test();
  obj.test( 2.2 );
 }
}
 

Compile Time Error	Runtime Error
int	float

A

It will give a compile time error because the 2.2 is a double value and there is no method "test" that takes double value.

What will be the output of the following program ?

class Test{

 public int test(int a){
  System.out.println("test1");
   return a;
  }

 public float test(int a){
  System.out.println("test2");
  return b;
 }

 public static void main(String args[]){
  Test obj = new Test();
  obj.test(2);
 }
}
 

Compile Time Error	test1
test2	test1 test2

A

The code will give a compile time error because both the methods test() takes same arguments so jvm will not be able to decide which method to call

What will be the output of the following program ?

class Test{

 public static void main(String args){
  System.out.println("main 1");
  }

 public static void main(String args[]){
  System.out.println("main 2");
 }
}
 

Compile Time Error	Runtime Error
main 1	main 2

D

Execution of the program always starts from the main method that takes an "array of strings" as the parameter. The above code containes the overloaded method main, when we will run the program it will print "main 2"

What will be the output of the following program ?

class A{

 public void test(){
  System.out.println("testA ");
  }

 public void test(String args){
  this.test();
  System.out.println("testA "+ args);
  }
}


class B extends A{

 public void test(){
  System.out.println("testB ");
  }


 public static void main(String args[]){
  A obj = new B();
  obj.test("check");
 }
}
 

testA testB check	testA check testA
testB testA check	Compile time error

C

Method test(String) of class A will be called first, "this.test()" will call the test() method of class A, but since test() method is overridden in class B, the call we go to test() method of class B and it will print "testB". Now control will again come back to test(String) method and it will print "testB check"

Finish Test