Hibernate Criteria Query to find List of Domain class.
Syntax to get List of domain Object
list can be used on the Criteria object as shown below.
criteria.list()
How to get a List of a Domain class using Hibernate's Criteria Query.
If we have a domain class Category as shown below.
Catgeory.class
package com.ekiras.domain; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import javax.persistence.OneToMany; import javax.persistence.Table; @Entity @Table(name="category") public class Category { public Category(){} public Category(Long id){ this.id = id; } public Category(Long id, String name){ this.id = id; this.name = name; } @Id @Column(nullable=false, name="id") @GeneratedValue(strategy=GenerationType.AUTO) private Long id; @Column(nullable=false, name="name") private String name; // Getters and Setters }
- Simplest way to get a list of a Domain class (Category) in our example is
sessionFactory.getCurrentSession().createCriteria(Category.class).list();
- You can use pagination in the following way with list()
@SuppressWarnings("unchecked") public List<Category>; list(Integer offset){ return sessionFactory.getCurrentSession() .createCriteria(Category.class) .setFirstResult(offset!=null?offset:0) .setMaxResults(10) .list(); }
- Use this method as a generic method to get a list of all the records of a domain in the database.
@SuppressWarnings("rawtypes") public List list(Class clazz){ return (List)getSession().createCriteria(clazz).list(); }
- You can Order your list according to any property like
public List<Category> list(Integer offset){ return getSession() .createCriteria(Category.class) .addOrder(Order.desc("id")) .list(); }
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